Thursday, December 22, 2016

The Infinite Art Tournament, Round FOUR Tiebreak: Kandinsky v. Benton


Third Thursday: Bringing big names to your mid-month!




This is an unusual Third Thursday matchup, which is perhaps appropriate given the confusion surrounding which Thursday was actually the third one of the month.  Nor is this quite a Semifinal match, although it might as well be.

According to plan, today... or perhaps last Thursday, whatever... was to be the Fifth Round match between the winners of Leonardo/Lissitsky and Benton/Goldsworthy.  But!  The Benton/Goldsworthy match ended in a tie.  So what we're going to do today is launch the first half of the tiebreaker that pits Benton and Goldsworthy against the artists in our other Round 4 tie, Kandinsky and Klee.  We'll do Klee/Goldsworthy at the regularly scheduled Round 4 spot in February, after which everything should calm down and get back to normal.

OH NO there has been an error of misattribution!!!  Probably by me!!  And there is nothing to be done for it except, as alert amateur art historian Matt Reilly suggests in the comments, a REDO!!!  Eventually.

6 comments:

Morgan said...

Benton

Alex Shields said...

Benton mostly because of the second to last one

Christine M. said...

Kandinsky

DrSchnell said...

Benton, but I want to vote for both of them.

Matt Reilly said...

My favorite was the 2nd to last Benton as well, so I looked it up. Isn't it 'Tragic Prelude' by John Steuart Curry? Maybe this one should be a redo ...
https://www.kshs.org/p/kansas-state-capitol-online-tour-tragic-prelude/16595

pfly said...

Oh this is hard. I probably would say Benton, but have a special connection to Kandinsky that makes it nigh impossible to vote against him. So I'm going to say Kandinsky, while kinda hoping Benton wins?