Thursday, September 14, 2017

The Infinite Art Tournament Left Bracket Third-Round Elimination: GRUDGE MATCH: De Hooch v. Homer!

Today's match features two artists last seen all the way back in 2015. Dutch master Pieter De Hooch (3-1, 23-22, .511) takes on American Winslow Homer (4-1, 48-19, .716). If you look at those statistics, Homer looks like the clear favorite -- except, when these two guys met in March 2014, it was Mr. De Hooch that ended up winning, seven votes to six. This of course makes this contest a Grudge Match, and means that Homer would have to beat De Hooch outright to stay alive. A tie would go to the Dutchman on the strength of his earlier win.

The artists that fell in the Third Round were Meindert Hobbema and Ferdinand Hodler.




Pieter De Hooch
1629 - 1684
Dutch
  • Overcame Gerrit van Honthorst, his countryman from the previous generation, in Round 1.
  • Shocked American Winslow Homer in Round 2 by a single vote. YOUR VOTE COUNTS!!!
  • Lost to Remedios Varo in Round 3.
  • Snuck by his near-contemporary Meindert Hobbema in the Left Bracket Third Round by a single vote. YOUR VOTE COUNTS!!!






Winslow Homer
1836 - 1910
American




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Vote for the artist of your choice in the comments, or any other way that works for you. Commentary and links to additional work are welcome. Polls open for at least one month past posting.

9 comments:

DrSchnell said...

Homer

Morgan said...

Both of these artists are wonderful! I'll vote Homer, but it's a slight preference.

Christine M. said...

Homer

Chance said...

Gotta go with Homer. There's so much more motion and expression in his work. De Hooch is just so... so... Dutch. So, Homer for the win.

Alex Shields said...

Doh! I'll go with Homer.

Jennifer said...

De Hooch.

Nichim said...

I still like De Hooch better.

pfly said...

Homer!

-pfly

Michael5000 said...

Susan votes for Homer.