Tuesday, March 20, 2018

Left Bracket Fourth Round Elimination: Homer v. Bouguereau!





This Left Bracket Fourth Round Elimination Match features Winslow Homer (6-1, 67-24, .736) and Adolphe William Bouguereau (5-1, 48-23, .676). Falling to them in the Fourth were, respectively, Frida Kahlo (3-2, 36-33, .522) and Andō Hiroshige (3-2, 30-30, .500).

Bouguereau's one loss came at the hands of Kahlo, which would seem to give Homer the logical advantage in this match.  Homer's own loss was to Pieter de Hooch, who has since been ousted from the Tournament -- by Homer himself, in a Grudge Match reversal.  You never know what to expect in the Infinite Art Tournament!


Winslow Homer
1836 - 1910
American







Adolphe William Bouguereau
1825 - 1905
French






11 comments:

Morgan said...

I am tempted to vote Bouguereau for pure technical skill, but today I'm going to go for Homer and his color and dynamism.

Christine M. said...

Homer

Hollis said...

Unlike Mr. Morgan, I'm for Bouguereau because of the technical skill.

Alex Shields said...

Bouguereau

Chance said...

My love for David-esque technical skill compels me to vote Bouguereau.

mrs.5000 said...

Oh, most definitely Homer.

boonec1974 said...

So Homer's going against... Uh excuse me, I just threw up in inside of my mouth a little. Please let this be when we can say goodbye to Bouguereau.

Michael5000 said...

I'll go with Homer. BUT EVEN NOW IT'S PRETTY CLOSE!!!

Nichim said...

Ugh, can I please have Kahlo vs. Hiroshige?

Homer. Other dude has skills, but the naked woman and Eros are just the wrong size relative to each other, and just quit it with the naked women already.

Michael5000 said...

Susan votes for Homer.

pfly said...

Homer